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XOR magic

Swap a and b with three XOR lines (no temporary variable), and write lonely(numbers) that returns the number that appears only once by XOR-ing everything together.

Learn

XOR (^) is 1 when the two bits differ. It has two lovely properties: x ^ x is 0, and x ^ 0 is x. So XOR-ing a number twice cancels it, which gives a way to swap without a spare variable, and a way to find the one number in a list that appears once when all others appear twice, because the pairs cancel.

Your task

Swap a and b with three XOR lines (no temporary variable), and write lonely(numbers) that returns the number that appears only once by XOR-ing everything together.

Stretch challenge

What if two numbers appear once? Think about splitting the list by one differing bit.

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Predict the output of AND, OR, XOR, NAND and NOR gates from their inputs.

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XOR magic: common questions

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