Example 1
Is 3,716 divisible by 4?
- Only the last two digits matter: 16.
- 16 ÷ 4 = 4 exactly.
Answer: Yes
🏅 Olympiad maths · session 2 of 49 · 60 minutes
Tell whether a big number divides exactly without doing the division. These rules make long questions short, and they are the key to the missing-digit puzzles that appear in every Olympiad.
A complete lesson · 60 minutes
Open this page with your learner and work down it, or press Teach this lesson to go through it one step at a time on a big screen. Every section has something to do.
Classes 4 to 7 · ages 9 to 13
Warm-up · think first
Yes. 1 + 0 + 0 + 0 + 0 + 0 + 2 = 3, and when the digits add to a multiple of 3, the number is a multiple of 3. Today you will learn why that works.
Teacher tip: Let them try the long division first for a minute. Then show the digit trick and enjoy the surprise.
Part 1 of 4 · learn, see, practise
A number divides by 2 when its last digit is even, by 5 when it ends in 0 or 5, and by 10 when it ends in 0.
For 4, look at the last two digits only, because 100 is already a multiple of 4. For 8, look at the last three digits, because 1000 is a multiple of 8.
Is 3,716 divisible by 4?
Answer: Yes
Is 51,240 divisible by 8?
Answer: Yes
Think first: Is 9,318 divisible by 4? By 2? Explain using the last digits.
Start with the warm-up and go as far as you can. The stretch questions are meant to be hard.
Part 2 of 4 · learn, see, practise
A number divides by 3 when the sum of its digits divides by 3, and by 9 when the sum divides by 9.
Why? 10 is 9 + 1, 100 is 99 + 1, 1000 is 999 + 1. So 472 = 4 × 99 + 7 × 9 + (4 + 7 + 2). The parts with 9s and 99s are always multiples of 9 (and of 3), so only the digit sum decides.
Is 7,482 divisible by 3? By 9?
Answer: By 3 yes, by 9 no
Think first: Find the remainder when 1,234 is divided by 9 using only the digit sum.
Start with the warm-up and go as far as you can. The stretch questions are meant to be hard.
Part 3 of 4 · learn, see, practise
For 11, add and subtract the digits in turn from the left: + − + −. If the answer is 0, 11, −11 or any multiple of 11, the number divides by 11.
6 = 2 × 3, so a number divides by 6 when it passes the rules for 2 and for 3. 12 = 3 × 4, so check 3 and 4. (Use numbers with no common factor: checking 2 and 6 does not prove 12.)
Is 9,163 divisible by 11?
Answer: Yes (9,163 = 11 × 833)
Is 2,316 divisible by 6?
Answer: Yes
Change each digit. The table shows which numbers divide it and the rule that tells you.
Think first: Use the tester to find the smallest 4-digit number that divides by 11.
Start with the warm-up and go as far as you can. The stretch questions are meant to be hard.
Part 4 of 4 · learn, see, practise
Olympiad questions hide a digit and ask what it must be. Write the rule with the unknown digit as a letter, then try the digits 0 to 9 that fit.
Always check your answer by dividing at the end.
Find the digit d so that 4d72 divides by 9.
Answer: d = 5
Find the digit d so that 35d divides by 6.
Answer: d = 4
Think first: Find d so that 7d6 divides by 11.
Start with the warm-up and go as far as you can. The stretch questions are meant to be hard.
Watch out
Ends in 4 does not mean divides by 4: 14 does not. Use the last two digits.
A digit sum of 12 means divisible by 3 but not by 9.
Divisible by 2 and 4 does not prove divisible by 8. Combine rules only for numbers with no common factor.
Class activity 1 of 3
Type a digit or a number for each one and press Check.
Class activity 2 of 3
Use the divisibility tester (or your rules) to find these numbers.
Class activity 3 of 3
Each puzzle has exactly one answer. Use the rules to cut down the choices.
Quiz · 8 questions
Pick an answer to see if it is right and why. Your best score is saved on this device.
After class · project
Make a pocket card of the rules with your own examples, and use it to solve one big hunt.
What to make: One card (or page) with all nine rules, examples, the explanation and the hunt answer with working.
Stretch: Find a rule for 7 on the internet or in a book and test it on three numbers.
| Look for | Done well when |
|---|---|
| Rules | All nine rules are correct |
| Examples | Every rule has a pass and a fail example |
| Why | The explanation for 9 uses 10 = 9 + 1 |
| Hunt | The smallest number is found with clear working |
Copy it onto paper or print the practice sheet.
Rule for 2: ______________ Passes: ____ Fails: ____ Rule for 3: ______________ Passes: ____ Fails: ____ … (one line for each of 4, 5, 6, 8, 9, 10, 11) Why the rule for 9 works: ________________________________ Smallest number divisible by 1 to 10: ________ How I found it: ____________
Homework
Try each on paper, then tap to see the answer and working. Or print the practice sheet.
By 5 yes (ends in 5); by 3: 9+8+7+6+5 = 35, no.
Last two digits d8 must divide by 4: d is even (08, 28, 48, 68, 88). Digit sum 14 + d must divide by 3: d = 1, 4 or 7. So d = 4 (648).
1 − 0 + 0 − 1 + 0 = 0, so yes (10,010 = 11 × 910).
Digit sum 20, and 20 = 2 × 9 + 2, so the remainder is 2.
For parents and teachers
Use it as it is, or stretch any part over two sessions. Each row links to the part of the page you need.
| Time | Part | The teacher | The learner |
|---|---|---|---|
| 0–4 min | Warm-up | Ask the warm-up question and wait for a guess. | Guess, then reason. |
| 4–12 min | Last digits | Teach, show the examples step by step, then the practice. | Practise up to the stretch question. |
| 12–21 min | Digit sums | Teach, use the interactive part, then the practice. | Practise; try the stretch. |
| 21–28 min | 11, 6 and 12 | Teach and show the examples. | Practise. |
| 28–35 min | Missing digits | Teach and show the examples. | Practise; the stretch can be homework. |
| 35–42 min | Activity 1 | Let the learner work alone; hint only after a wrong check. | Solve and check. |
| 42–49 min | Activity 2 | Follow the steps together for the first item. | Finish the investigation. |
| 49–55 min | Activity 3 | Set as homework if time is short. | Solve the puzzles. |
| 55–59 min | Quiz | Run the quiz and review mistakes. | Answer and read why. |
| 59–60 min | Set the project | Show the template and the due date. | Start the project. |
Stay with 2, 5, 10, 3 and 9 and use the tester to check every guess.
Find all digits a and b so that the number 7a5b divides by 99 (it must divide by 9 and by 11).
FAQ
2, 5 and 10 use the last digit; 4 uses the last two digits and 8 the last three; 3 and 9 use the digit sum; 11 uses the alternating sum; 6 and 12 combine two rules.
Every place value is one more than a multiple of 9 (10 = 9 + 1, 100 = 99 + 1), so a number and its digit sum leave the same remainder when divided by 9.
Write the rule with the missing digit as a letter, list which digits 0 to 9 make it work, and check the answer by dividing.
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